previous apptitude question's.....!!!!

Question 1

Aravamudhan gives Babu as many rupees as Babu has and Chiranjeevi as many rupees as Chiranjeevi has. Similarly, Babu then gives Aravamudhan and Chiranjeevi as many rupees as each of them has. Chiranjeevi, similarly gives Aravamudhan and Babu as many rupees as each of them has. Now finally each of them has Rs.32, with how many rupees does Aravamudhan start?

a)52 b)56 c)60 d)62

Answer : a)52

Solution :

We have to take a bottom up (reverse) approach to tackle these kinds of problems. Below are the steps to solve this problem.

                                                          Aravamudhan  Babu Chiranjeevi

Finally                                     32  32  32
Before Chiranjeevi gives        16  16  64 
Before Babu gives                   8   56  32 
Before Aravamudhan gives     52  28  16 

Hence, Aravamudhan start with Rs 52.

Question 2

Fifty one books are arranged from left to right in order of increasing prices. The price of each book differs by Rs. 2 from that of each adjacent book. For the price of the book at the extreme right a buyer can buy the middle book and an adjacent one. Then, which of the following statements is correct ?

a) The adjacent book referred to is at the left of the middle magazine.
b) The middle book sells for Rs. 56
c) The most expensive book sells for Rs.116
d) None of the above statements is correct.

Answer : a) The adjacent book referred to is at the left of the middle magazine.

Solution :

Let the price of the first book be B
Price of the last book (51st) will be B + (2 x 50)
= B + 100
Price of the middle book = B + (2 x 25) = B + 50
Price of the book to the left of middle book = Price of the middle book – 2 = B + 48
But, from the question, we can infer that,
Price of the middle book + Price of the book to the left of middle book = Price of the last book.
B + 50 + B + 48 = B + 100
B = 2
Instead if the buyer buys the middle book and the book adjacent right side
B + 50 + B + 52 = B + 100
B = -2 (not possible)
Cost of middle book = 2 + 50 = 52
Price of the Most expensive book (i.e last book) = B + 100 = 2 + 100 = Rs.102.
Hence a) is correct.

Question 3

A group of six friends are sitting around a hexagonal table, each one at one corner of the hexagon. (facing the centre inside) Raman is sitting opposite to Ramesh. Jolly is sitting next to Seema. Neeta is sitting opposite to Seema, but not next to Ram. Amit has a person sitting between Ramesh and himself. If Neeta sits to the right of amit, then who is sitting to the left of Amit?

a)Ramesh b)Raman c)Jolly d) Seema

Answer : b) Raman

Solution :

Based on the information provided, seating pattern will be drawn as above
Clockwise = AMIT – RAMAN - SEEMA - JOLLY- RAMESH - NEETA

Question 4

The average speed of a bus from Koyambedu to Salem is 57 km per hour. The bus is scheduled to leave Koyambedu Bus station at 10 pm and reach Salem at 4.35 am on the next day. The distance between Salem and Koyambedu bus station is 342 km. On the way in between Koyambedu and Salem a halt is scheduled compulsorily. Find out the duration of this halt scheduled?

a) 45 minutes b) 35 minutes c) 60 minutes d) cannot be determined

Answer : b)35 minutes

Solution :

Distance between the two places = 342 km
Average speed is 57 km per hour
Travel time taken = 342/57 = 6 hours
Bus starts at 10 pm. So if the bus travels without halt it will reach Salem by 4 am
But it is scheduled to reach at 4.35 allowing for halt of 35 minutes

Question 5

Ramakanth drives 150 kilometres to the railway station in 3 hours and 20 minutes. He returns from the railway station to the starting place in 4 hours and 10 minutes. Let A be the average rate for the entire trip. Then the average rate for the trip of going to the railway station exceeds A, in kilometers per hour, by:

a) 4 b) 5 c) 3 d) 2

Answer : b)5

Solution :

Average rate –from starting point to railway station = distance / speed of upward journey = 150 /3 1/3 = 45 km/hour
Average rate for return from railway station to starting place = distance / speed of downward journey = 150/ 4 1/6 = 36 km/hour
Total distance combining upward and return journeys = 300 km
Average rate 'A' = Total Distance / (Speed of Upward Journey + Speed of Return Journey) = 300 /( 3 1/3 + 4 1/6 )
= 40 km.
So the average rate for trip of going to the railway station exceeds A by 45-40 = 5 km

Question 6

Dhoni, Tendulkar and Altaf participate in a ten kilometers race. Dhoni beats Tendular by 2 kilometres. Dhoni beats Altaf by 4 kilometers. If the runners maintain constant speeds throughout the race, by how many kilometers does Tendulkar beat Altaf in a 30 kilometres race?

a) 9.5 b) 4.5 c) 6.5 d) 7.5

Answer : d)7.5

Solution :

For a duration when Tendulkar runs 8 kilometres Altaf runs 6 kilometres
when Tendulkar runs 30 kilometres Altaf will run 30/8 x 6 = 22.5 km
So Tendulkar will beat Altaf by 7.5 kilometres.

Question 7

The marked price of a clock is Rs.6400. It is to be sold at Rs.4896 at two successive discounts. If the first discount is 10%, the second discount is

a) 10% b)4% c)15% d)20%

Answer : c)15%

Solution :

Marked price = Rs. 6400
Price after first discount of 10% = 6400 x 0.9 = Rs.5760
Selling price = Rs.4896
Therefore second discount = (Price after first discount - Selling Price) / Price after first discount X 100 = (5760 - 4896) / 5760 x 100 = 15%

Question 8

A shopkeeper marks his goods 30% above the cost price and then allows 15% discount on it. What is the cost price of an article on which he gains Rs.840?

a)Rs.6400 b)Rs.8000 c)Rs.7000 d) Rs.9000

Answer : b)Rs.8000

Solution :

Let the cost price be Rs.100
Marked price – Rs.130
Discount allowed – 15%
Then selling price will be 130 -19.5 = 110.5
The gain when cost price is Rs.100 = 110.5 - 100 = 10.5
Cost Price Gain
100 10.5
? 840
Cost Price when gain is Rs.840 = 100/10.5 x 840 = 8000

Question 9

A shopkeeper sells a DVD player for Rs. 2880 and he makes the same percentage of profit as the loss percentage on selling price he makes if he sells at Rs.1920. What is the price at which the shopkeeper should sell this DVD player if he wants to make 30% profit?

a) Rs.3000 b)Rs.3120 c)Rs.3240 d) Rs. 3240

Answer : b)Rs.3120

Solution :

Let the cost of price of DVD player be D
Profit percentage when he sells at Rs.2880 = Loss percentage when he sells at 1920
i.e., (2880-D) / D x 100 = (D - 1920) / D x 100
2880 -D = D – 1920
2880 + 1920 = D + D
4800 = 2 D
D = Rs. 2400

Cost price = Rs. 2400. He wants to make 30% profit. (In the absence of special mention profit is always calculated on cost price.)
The desired profit amount = 30% of Rs.2400 = (2400 x 30) / 100 = 720.
Hence, The selling price = CP + Desired Profit = 2400 + 720 = Rs. 3120.